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Equation of parabola which is symmetric about x-axis with vertex (0, 0) and pass through (3, 6).(a) y^2=6x(b) x^2=12y(c) y^2=12x(d) x^2=6yI got this question by my school teacher while I was bunking the class.Question is from Conic Sections topic in portion Conic Sections of Mathematics – Class 11

Answer»

Correct OPTION is (c) y^2=12x

For explanation I would say: EQUATION of parabola which is symmetric about x-axis with vertex (0, 0) is y^2=4ax

Since parabola PASS through (3, 6) then 6^2=4a*3 => a=3.

So, equation is y^2=12x.



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