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Find the vertex of the parabola y^2=4ax.(a) (0, 4)(b) (0, 0)(c) (4, 0)(d) (0, -4)The question was asked during an interview for a job.My question is based upon Conic Sections topic in section Conic Sections of Mathematics – Class 11

Answer»

The CORRECT option is (B) (0, 0)

Explanation: Vertex is close END point of the PARABOLA i.e. origin (0, 0) as it SATISFIES the equation (y-0)^2=4a(x-0) also.



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