1.

Equilibrium concentration of SO_(2)Cl_(2) formed from 3 moles of SO_(2) and 4 moles of Cl_(2) present in a litre flask is 1.5 mole/L. Calculate K_(c ).

Answer»

SOLUTION :`SO_(2)+Cl_(2) hArr SO_(2)Cl_(2)`
`{:("Initial NO. of moles",3,4,0),("At equilibrium",,3-x,4-x x):}`
Concentration of `SO_(2)Cl_(2)` at equilibrium is 1.5 moles.
x=1.5 moles/L
Concentration of `SO_(2)` at equilibrium =3-1.5=1.5 moles/L
`therefore K_(c )=([SO_(2)Cl_(2)])/([SO_(2)][Cl_(2)])=(1.5)/(1.5xx2.5)=0.4 " mole" // L`


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