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Equivalent conductance of 1M `CH_(3)COOH` is `10ohm^(-1) cm^(2) "equiv"^(-1)` and that at inifinite dilution is 200 `ohm^(-1) cm^(2) "equiv"^(-1)`. Hence, % ionisation of `CH_(3)COOJ` is:A. `5%`B. `2%`C. `4%`D. `1%` |
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Answer» Correct Answer - A `alpha=(^^_(infty)^(C))/(^^_(m)^(infty))` |
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