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esFour particles each of mass M, are located at the vertices of a square with side L. Thegravitational potential due to this at the centre of the square isn, menu-

Answer»

Net force acting on any one particle M=GM²/(2R)²+GM²/(R√2)²Cos45°+GM²/(R√2)²Cos45° M=GM²/R² [1/4+1/√2] This force will equal to centripetal force So,. Mv²/R=GM²/R²[1/4+1/√2] V=√[GM²/4R(1+2√2)] V=1/2√[GM/R(2√2+1)]



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