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Evaluate : `(i)" "sqrt(-25)xx sqrt(-49)" "(ii)" "sqrt(-36)xx sqrt(16)` |
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Answer» We have `(i)" "sqrt(-25)xxsqrt(-49)=(5i)xx(7i)=(35xxi^(2))=35 xx (-1) = -35`. `(ii)" "sqrt(-36) xx sqrt(16) = (6i) xx 4 = 24 i`. |
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