1.

Evaluate:`("lim")_(xvecpi/2)(1+cos2x)/((pi-2x)^2)`

Answer» Correct Answer - `1/2`
Putting `(pi-2x)=t,` we have
giving limit `=lim_(t to a)(1+cos(pi-t))/(t^(2))=2/4.lim_(t to0){(sin(t//2))/((t//2))}^(2)=((1)/(2)xx1^(2))=1/2.`


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