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Evaluate:`("lim")_(xvecpi/2)(1+cos2x)/((pi-2x)^2)` |
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Answer» Correct Answer - `1/2` Putting `(pi-2x)=t,` we have giving limit `=lim_(t to a)(1+cos(pi-t))/(t^(2))=2/4.lim_(t to0){(sin(t//2))/((t//2))}^(2)=((1)/(2)xx1^(2))=1/2.` |
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