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Evaluate : `overset2underset0int`

Answer» `int_0^2 (1)/((1 +3 x))dx = [log(1+3x)/(3)]_0^2 = (1)/(3)[ log(1 +3xx2) - log (1+3xx0)]`
`= (1)/(3) [log 7-log 1] = (1)/(3) (log 7- 0) = (1)/(3) log7`


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