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Evaluate ∫ sec6x dx |
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Answer» ∫ sec6x dx In this integral we will use the formula, 1+tan2x = sec2x I = ∫sec2x sec4x dx = ∫sec2x (1 + tan2x)2dx Now, Put tan x = t which means sec2xdx = dt, I = ∫(1+ t2)2dt = ∫(1+t4+2t2) dt Now put the value of t, which is t = tan x in above integral- I = tanx + \(\frac{tan^5x}{5}\)+ 2.\(\frac{tan^3x}{3}\) |
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