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Evaluate:\(\int\frac{tanx\,sec^2x}{(1-tan^2x)}dx\)∫tanx sec2x/(1 - tan2x)dx |
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Answer» Let 1 - tan2 x = t -2 tan x. sec2 x dx = dt -1/2∫dt/t = -1/2 logt + c \(\int\frac{tanx\,sec^2x}{(1-tan^2x)}dx\) = -1/2 log|1 - tan2x| + c |
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