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Evaluate:\(\int\frac{sec^2x}{{cosec^2 x}}dx\)∫sec2x/cosec2xdx

Answer»

\(\frac{sec^2x}{{cosec^2 x}}\) = tan2x

∫ tan2x dx = ∫ (sec2x - 1)dx

\(\int\frac{sec^2x}{{cosec^2 x}}dx\) = tan x - x + c



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