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Evaluate:\(\int\frac{sec^2x}{{cosec^2 x}}dx\)∫sec2x/cosec2xdx |
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Answer» \(\frac{sec^2x}{{cosec^2 x}}\) = tan2x ∫ tan2x dx = ∫ (sec2x - 1)dx \(\int\frac{sec^2x}{{cosec^2 x}}dx\) = tan x - x + c |
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