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Evaluate:(sin 72° + cos 18°) (sin 72° – cos 18°) |
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Answer» We know that, sin (90 – θ) = cos θ So, the given can be expressed as (sin 72° + cos 18°) (sin (90 – 18)° – cos 18°) = (sin 72° + cos 18°) (cos 18° – cos 18°) = (sin 72° + cos 18°) x 0 = 0 |
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