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Evaluate `sqrt(24-10i)`. |
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Answer» Let `sqrt(-24-10i)=(x+iy)." "...(i)` On squaring both sides of (i), we get `(-24-10i)=(x^(2)-y^(2))-i(2xy)." "...(ii)` On comparing real parts and imaginary parts on both sides of (ii), we get `x^(2)-y^(2)=-24 and 2xy = 10` `rArr" "x^(2)-y^(2)=-24 and xy = 5` `rArr" "(x^(2)+y^(2))=sqrt((x^(2)-y^(2))^(2)+4x^(2)y^(2))=sqrt((-24)^(2)+4 xx 24)=sqrt(676)=26` `rArr" "x^(2)-y^(2)=-24 and x^(2)+y^(2)=26` `rArr" "2x^(2)=2 and 2y^(2)=50` `x^(2)=1 and y^(2)=25 rArr x = +-1 and y = +-5`. Since `xy gt 0`, so x and y are of the same sign. `therefore" "sqrt(-24-10i)=(1-5i)or(-1+5i)`. |
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