1.

Evalute `lim_(xrarr0)((e^(3x)-1)/(x)).`

Answer» `lim_(xto1)((e^(3x)-1)/(x))=lim_(3xto0){((e^(3x)-1)/(3x))xx3}" "[because(xto0)implies(3xto0)]`
`=3xxlim_(yto0)((e^(y)-1)/(y))where y=3x`
`=(3xx1)=3" "[becauselim_(xto0)((e^(y)-1)/(y))=1].`


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