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Example 10.3 An object is thrownvertically upwards and rises to a heightof 10 m. Calculate (i) the velocity withwhich the object was thrown upwardsand (i) the time taken by the object toreach the highest point.

Answer»

Let velocity of object is u we know, at 10m height object will be rest . so, final velocity = 0

A/C to kinematics equations, v² = u² + 2aS 0 = u² +2(-g) × 10 0 = u² - 2 × 100 u² = 200u = 10√2 m/s

Time taken by the object to reach the highest point is t v = u + at 0 = 10√2 - 10t t = 10√2/10 sec t = √2 sec

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