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Example 13.1 Given the mass of iron nucleus as 55.85u and A=56.find the nuclear density? |
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Answer» The formula is Density (n)= Mass of nuclei/nuclear volume Nuclear volume= 4/3 π r³ To find radius:- r= r° (a)^¹/³ R= 1.3×10^-15(56)^1/3 R=3.825×1.3×10^-15 R=4.97×10^-15 R³==122.76×10^-45 4/3πr³= 513.96×10^-45 Density = mass/volumeDensity = 55×1.6×10^-27Density= 88×10^18/513.96Density = 0.1812×10^18Density =1.812×10^17 kg /m³. |
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