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Example 13.1 Given the mass of iron nucleus as 55.85u and A=56.find the nuclear density?

Answer»

The formula is

Density (n)= Mass of nuclei/nuclear volume

Nuclear volume= 4/3 π r³

To find radius:-

r= r° (a)^¹/³

R= 1.3×10^-15(56)^1/3

R=3.825×1.3×10^-15

R=4.97×10^-15

R³==122.76×10^-45

4/3πr³= 513.96×10^-45

Density = mass/volumeDensity = 55×1.6×10^-27Density= 88×10^18/513.96Density = 0.1812×10^18Density =1.812×10^17 kg /m³.



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