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Example 14. A light of wavelength 6000 A in air, enters amedium with refractive index 1.5. What will be the frequencyand wavelength of light in that medium ?IIT 971

Answer»

c = Speed of light in air → 3 X 10^8 m/s

W → Wavelength

n → Refractive index of the medium = 1.5

W in air = 6000 A = 6 X 10^-7 metres

λ → Frequency in air = c / W in air = 5 X 10^14 Hz

n = W in air / W in the medium

1.5 = 6000 / W in the medium

W in the medium =4000 A

Magnitude of frequency depends upon the light producing source hence it remains constant throughout (5 X 10^14 Hz) .



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