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Example 14. A light of wavelength 6000 A in air, enters amedium with refractive index 1.5. What will be the frequencyand wavelength of light in that medium ?IIT 971 |
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Answer» c = Speed of light in air → 3 X 10^8 m/s W → Wavelength n → Refractive index of the medium = 1.5 W in air = 6000 A = 6 X 10^-7 metres λ → Frequency in air = c / W in air = 5 X 10^14 Hz n = W in air / W in the medium 1.5 = 6000 / W in the medium W in the medium =4000 A Magnitude of frequency depends upon the light producing source hence it remains constant throughout (5 X 10^14 Hz) . |
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