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Example 2.15 Let us consider an equation2here m is the mass of the body, u itslocity, g is the acceleration due toavity and h is the height. Checkhether this equation is dimensionallyrect |
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Answer» Here we have to check the dimensions of 1/2(m)v² and mgh foe 1/2mv² the dimension is M(L/T)² = ML²T-² now for mgh , the dimension is M(L/T²)L = ML²T-². so we can say that the equation is dimensionally correct |
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