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Example 3.2The distance travelled by a particle in time t is givenby s (2-5 m/s t. Find (a) the average speed of theparticle during the time 0 to 5 0 s, and (b) theinstantaneous speed at t = 5.0 s. |
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Answer» how we multiplied with 5 in B part ?? velocity is 5×t ... so, when t = 5 sec then v. = 5×5 = 25m/s but it is ask to find instantaneous speed at t= 5 that's why only we put t = 5 , for example if it was asked velocity at t = 0 , then v = 5×0 = 0Velocity at t = 1 , then v = 5×1 = 5velocity at t = 2 , then v = 5×2 = 10velocity at t = 3 , then v = 5×3 = 15 velocity will change every second like this ↑↑ |
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