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Example 34 A particle is dropped from the top of a tower.Its displacement in the first three seconds and in the lastsecond is the same. Find the height of the tower. |
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Answer» Let the height of the tower be H...so, total time is t = √2H/g Displacement in 1st three seconds is h3 = 1/2*g*(3)² = 9g/2 =45m also displacement in nth second is hn = g/2*(2√(2H/g)-1) but h3 = hn so, 45 = 5*(2*(√(2H/g) -1)=> 9 = 2*√H/5 -1 => 10 = 2√H/5=> 5 = √H/5 => H/5 = 25 so, H = 25*5 = 125m |
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