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Example 5.10. An object placed 50 cm from a lens produces a virtual image ata distance of 10 cm in front of the lens. Draw a diagram to show the formationof image and calculate the focal length of the lens. |
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Answer» Object distance=-50 cm(applying sign convention)Since the image distance is lesser than the object distance and a virtual image is formed, it's a concave lens.(v=-10)We are supposed to use lens formula:-1/f=1/v-1/uf is -vev is -veu is -veon simplifying we getf=25/4 or 6.25 cm.magnification=-(v/u) =-10/50=-0.2 |
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