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Example 9.1 A constant force acts on anobject of mass 5 kg for a duration of2 s. It increases the object's velocityfrom 3 m s1 to 7 m s1. Find themagnitude of the applied force. Now, ifthe force was applied for a duration of5 s, what would be the final velocity ofthe object?

Answer»

Let the force be F,Mass is M,time for which it is accelerated = 2svelocity is increased from 3m/s to 7m/sso, acceleration is , a = (7-3)/2 = 2m/s²The force applied is, F = ma = (5)(2) = 10 NNow, the force is applied for 5s, the velocity after 5s will be,v=u+at=> v =3+(2)(5)=>v=13m/s , this is final velocity



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