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Example 9.7 A girl of mass 40 kg jumpswith a horizontal velocity of 5 ms ontoa stationary cart with frictionlesswheels. The mass of the cart is 3 kgWhat is her velocity as the cart startsmoving? Assume that there is noexternal unbalanced force working inthe horizontal direction.

Answer»

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we will use conservation of linear momentum

initial momentum of the system is =mass of girl × velocity = 40× 5 = 200kg-m/s

and when she will jump the net mass of the system will be 40+3 = 43 kg

and both will have same final Velocity V

so, final momentum will be 43*(V)

now mi = mf => 200 = 43v => v = 200/43 = 4.65 m/s



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