Explain the nature of the covalent found using the bond formation in C

1.	Explain the nature of the covalent found using the bond formation in CH_(3)Cl.
Answer» Solution :The atomic numbers of carbon, hydrogen and chlorine are 6, 1 and 17 respectively. Hence, their electronic configuration may be written as follows : This indicates that, carbon REQUIRES 4 electrons to COMPLETE its octet, hydrogen requires 1 electron to complete its DUPLET and chlorine requires 1 electron to complete its octet. Therefore, carbon shares its four electrons, one electron each with three hydrogen atoms and one electron with chlorine atom to form four covalent BONDS completing its octet. Thus, carbon attains the stable electronic configuration of nearest NOBLE gas neon, hydrogen attains the electronic configuration of noble gas helium, while chlorine acquires the electronic configuration of noble gas argon. In short, chloromethane forms three `C-H` and one C - Cl covalent bonds.

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