1.

Explain the series connection of parallel resistors.

Answer»

Solution :(i) If we consider the connectrion of a set of parallel resistors that are connected in SERIES we get a series - parallel circuit
(ii) Let `R_(1)` and `R_(2)` be connected in parallel to give an effective RESISTANCE of `RP_(1)`.
(iii) Similarly, let `R_(3)` and `R_(4)` be connected in parallel to give an effective resistance of `RP_(2)`.
(iv) Then, both of these parallel segment are connected in series.
(v) Using equation `(1)/(R_(p))=(1)/(R_(1))+(1)/(R_(2))+(1)/(R_(3))` we get
`(1)/(R_(p_(1)))=(1)/(R_(1))+(1)/(R_(2))`
`(1)/(R_(p_(2)))=(1)/(R_(3))+(1)/(R_(4))`
Finally, using equation the `R_(S)=R_(1)+R_(2)+R_(3)` NET effective resistance is GIVEN by `R_("total")=R_(P_(1))+R_(P_(2))`


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