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Express the change in internal energy of a system when (i) No heat is absorbed by the system from the surrounding, but work (w) is done on the system. What type of wall does the system have? (ii) No work is done on the system, but q amount of heat is taken out from the system and given to the surrounding. What type of wall does the system have? (iii) w amount of work is done by the system and q amount of heat is supplied to the system. What type of system would it be ? |
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Answer» (i) Here, `q = 0 :. Delta U = q+w= 0 + w_(ad) = w_(ad)` As no heat is absorbed by the system, the wall id adiabatic. (ii) Here, ` w= 0 , q= -q :. Delta U = q + w= -q+0= -q` As heat is taken out, the system must be having thermally conducting walls. (iii) `w = -w , q= +q` `:. Delta u = q+ w = q-w` As work is done by the system on absorbing heat, it must be a closed system. |
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