f ,In diffraction using single slit, a slit of width a is illuminated

1.	f ,In diffraction using single slit, a slit of width a is illuminated by white light. For red light (minima is obtained for 0 30°. Then the value of a will be(1) 3250 A(3) 1.24 um6500 A), the first(2) 6.5 x 104(4) 2.6 x 104
Answer» from the relation.. of 1st order minima condition.. asin∅ = m(wavelength) , where m = 1 , sin∅ = sin30 = 1/2. so, a = 1× 650 × 10^(-9) / 1/2 = 1350×10^-10 = 1.3× 10^(-7) m answer is 1.3 × 10^(-7)m and the closest value is option C.

f ,In diffraction using single slit, a slit of width a is illuminated by white light. For red light (minima is obtained for 0 30°. Then the value of a will be(1) 3250 A(3) 1.24 um6500 A), the first(2) 6.5 x 104(4) 2.6 x 104

Answer»

from the relation.. of 1st order minima condition..

asin∅ = m(wavelength) , where m = 1 , sin∅ = sin30 = 1/2.

so, a = 1× 650 × 10^(-9) / 1/2 = 1350×10^-10 = 1.3× 10^(-7) m

answer is 1.3 × 10^(-7)m

and the closest value is option C.

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f ,In diffraction using single slit, a slit of width a is illuminated by white light. For red light (minima is obtained for 0 30°. Then the value of a will be(1) 3250 A(3) 1.24 um6500 A), the first(2) 6.5 x 104(4) 2.6 x 104

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