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`f:R->R` is defined as `f(x)=2x+|x|` then `f(3x)-f(-x)-4x=`A. f(x)B. `-f(x)`C. `f(-x)`D. 2f(x) |
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Answer» Correct Answer - D `f : R rarr R` `f(x) = 2x + |x|` When `x ge 0`, then f(x) = 2x + x = 3x When `x lt 0`, then f(x) = 2x - x = x Now, when `x ge 0` `f(3x)-f(-x)-4x=3x-(-3x)-4x=2x=2f(x)` |
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