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(Figure 3.139) shows three circular arcs, each of radius `R` and total charge as indicated. The net electric potential at the center of curvature. .A. `q/(2 pi epsilon_0 R)`B. `(5 Q)/(12 pi epsilon_0 R)`C. `(3 Q)/(32 pi epsilon_0 R)`D. none of these. |
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Answer» Correct Answer - a Charge can be considered as located at a distance `R` from the center. Total charge is `(Q - 2 Q+ 3Q) = 2 Q` Hence, `V = (1)/(4 pi epsilon_0) (2 Q)/r = Q/(2 pi epsilon_0 R)`. |
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