Figure shows an arrangements of masses hanging from a ceilling. In equilibrium each rod is horizontal, has negligible mass and extends three times as far to the right of the wire supporting is as to the left. If mass `m_(4)` is `48 kg,` then `(m_(3))/(m_(2))` is

Figure shows an arrangements of masses hanging from a ceilling. In equ

1.	Figure shows an arrangements of masses hanging from a ceilling. In equilibrium each rod is horizontal, has negligible mass and extends three times as far to the right of the wire supporting is as to the left. If mass `m_(4)` is `48 kg,` then `(m_(3))/(m_(2))` is
Answer» Correct Answer - 4 `m_(2)gxx1=m_(1)gxx3`i.e., `m_(2)=3m_(1)` `4m_(1)gxx3=m_(3)g i.e., m_(3)=12 m_(1)` `16m_(1)gxx3=m_(4)g` `m_(1)=1 kg`

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Figure shows an arrangements of masses hanging from a ceilling. In equilibrium each rod is horizontal, has negligible mass and extends three times as far to the right of the wire supporting is as to the left. If mass `m_(4)` is `48 kg,` then `(m_(3))/(m_(2))` is

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