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Fill in the blanks (a) `._(92)^(235)U+._(0)^(1)n rarr ._(52)^(137)A+ ._(40)^(97) B + __________. (b) `._(34)^(82) Se rarr 2 _(-1)^(0)e+__________`. |
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Answer» Correct Answer - (a) `2_(0)^(1)n` , (b) ` ._(36)^(82) Kr` `._(92)^(235)U+_(0)^(1)nrarr ._(52)^(137)A+_(40)^(97)B+X ._(0)n^(1)` (as the reaction is balanced with respect to nuclear charge, the missing particle must be neutral i.e. neutron) Applying mass nuclear charge balancing `34=-2+z` `z=36" "` (This implies element is kr) Applying mass number balancing `82=0+A` `A=82` Final balanced reaction is `._(34)^(82)Se rarr 2 ._(-1)^(0)e + _(36)^(82) Kr` |
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