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Find a point on the x-axis which is equidistant from the points (7, 6) and (-3, 4). |
Answer» Let A(7, 6) and B(-3, 4) be the given points. Let P(x, 0) be the point on the x-axis such that PA = PB So, PA2 = PB2 (x – 7)2 + (0 – 6)2 = (x + 3)2 + (0 – 4)2 x2 + 49 – 14x + 36 = x2 + 9 + 6x + 16 -20x = -60 x = 3 Therefore, the point on x-axis is (3, 0). |
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