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Find a point on the y-axis which is equidistant from A(-4, 3) and B(5, 2). |
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Answer» Let the point on the y-axis be P(0, y) Given: P is equidistant from A(- 4, 3) and B(5, 2). i.e., PA = PB ⇒ \(\sqrt{(-4-0)^2+(3-y)^2}\) = \(\sqrt{(5-0)^2+(2-y)^2}\) Squaring both sides, we get ⇒ (- 4 – 0)2 + (3 – y)2 = (5 – 0)2 + (2 – y)2 ⇒ 16 + 9 – 6y + y2 = 25 + 4 – 4y + y2 ⇒ 25 – 6y = 29 – 4y ⇒ 2y = - 4 ⇒ y = - 2 Therefore, the required point on the y-axis is (0, - 2). |
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