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Find a unit vectorperpendicular to the plane determined by the points `(1,-1,2),(2,0,-1)a n d(0,2,1)dot` |
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Answer» Given points are A(1,-1,2),B(2,0,-1) and C(0,2,1) `Rightarrow vec(AB)=veca=hati+hatj-3hatk,vec(BC)=vecb=-2hati+2hatj+2hatk` `vecaxxvecb=|{:(hati,hatj,hatk),(1,1,-3),(-2,2,2):}|=8hati+4hatj+4hatk` Hence, Unit vector `vecaxxvecb=|{:(hati,hatj,hatk),(1,1,-3),(-2,2,2):}|=8hati+4hatj+4hatk` |
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