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Find all pairs of consecutive odd natural numbers, both of which are larger than 10, such that their sum is less than 40. |
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Answer» Let x be the smaller of the two consecutive odd natural number, so that the other one is x + 2. Given x > 10 and x + (x + 2) < 40 ⇒ 2x < 38 ⇒ x < 19 ∴10 < x < 19 Since x is an odd number, x can take the values 11,13, 15 and 17. ∴ Required possible pairs are (11, 13), (13, 15), (15, 17), (17,19). |
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