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Let a, b, c be the lengths of the sides of a right angled triangle, the hypotenuse having the length c, then a + b is(a) > 2c (b) < √2c (c) > √2c (d) < 2c |
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Answer» (b) < √2c Since a, b, c are the lengths of the sides of a right triangle having hypotenuse of length c, therefore a2 + b2 = c2 (Pythagoras, Theoram) Now, a > 0, b > 0 ⇒ (a – b)2 > 0 ⇒ a2 + b2 > 2ab ⇒ 2(a2 + b2) > a2 + b2 + 2ab ⇒ 2 (a2 + b2) > (a + b)2 ⇒ 2c2 > (a + b)2 ⇒ (a + b)2 < 2c2 ⇒ (a + b) < √2c. |
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