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Find all pairs of consecutive odd positive integers both of which are smaller than 8 such that their sum is more than 10.(a) (5,7)(b) (3,5), (5,7)(c) (3,5), (5,7), (7,9)(d) (5,7), (7,9)I got this question during an online exam.My question comes from Algebraic Solutions of Linear Inequalities in One Variable and their Graphical Representation in section Linear Inequalities of Mathematics – Class 11

Answer»

Right answer is (a) (5,7)

The explanation: Let TWO numbers be x and x+2.

x + x+2 >10 => 2x>8 => x>4

and x<8

and x+2<8 => x<6.

4 x can be 5.

For x =5, x+2=7

So, Pairs of odd consecutive positive integers are (5,7).


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