1.

Inequations involved in the given region are____________(a) 2x+y≥6, x≥0, y≥0(b) 2x+y>6, x≥0, y≥0(c) 2x+y

Answer»

Right option is (d) 2x+y≤6, x≥0, y≥0

To EXPLAIN I WOULD SAY: Since region INVOLVES 1^st quadrant so x≥0, y≥0.

Two points on line are (0,6) and (3,0).

(y-6)/(0-6) = (x-0)/(3-0)

=>(y-6)/(-6) = x/3

=>y-6=-2x => 2x+y=6

2x+y≤6 since (0,0) should ALSO satisfy.

So, 2x+y≤6, x≥0, y≥0.


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