1.

Find angle `theta`, 0 < `theta` < `pi/2` , which increase twice as fast as sine

Answer» Let `theta` increases twice as fast at its sine.
`rArr theta=2sintheta`
Now, on differentiating both sides w.r.t., we get
`(d(theta))/(dt) =2.costheta.(d(theta))/(dt) rArr 1=2costheta`
`rArr 1/2 = costheta rArr costheta = cospi/3`.
So, the required angle is `pi/3`


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