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Find angle `theta`, 0 < `theta` < `pi/2` , which increase twice as fast as sine |
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Answer» Let `theta` increases twice as fast at its sine. `rArr theta=2sintheta` Now, on differentiating both sides w.r.t., we get `(d(theta))/(dt) =2.costheta.(d(theta))/(dt) rArr 1=2costheta` `rArr 1/2 = costheta rArr costheta = cospi/3`. So, the required angle is `pi/3` |
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