1.

Find dy/dxa ) (x+y)^2 = 4 b) x²y+xy²=6

Answer»

a ) (x+y)^2 = 4 Differentiating both sides w.rt x d ( (x+y)^2) /dx = d4/dx2(x+y ) ( 1+ dy/dx) = 0 1+dy/dx = 0 dy/dx = -1

b) Differentiating both sides w.rt x 2xy + x^2 (dy/dx) + y^2 + 2xy (dy/dx) = 0 (x^2 + 2xy) (dy/dx) = -2xy- y^2 dy/dx = (-2xy- y^2)/(x^2+2xy)



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