FIND EQUIVALENT RESISTANCE OF THE FOLLOWING COMBINATION.

1.	FIND EQUIVALENT RESISTANCE OF THE FOLLOWING COMBINATION.
Answer» Given Four RESISTORS of 2Ω are CONNECTED parallely. They further are connected in SERIES with a 20Ω resistor To Find Equivalent resistance Solution ☯ The equivalent resistance of a parallel COMBINATION is given by, 1/R = 1/R₁ + 1/R₂ ... + 1/Rₙ ━━━━━━━━━━━━━━━━━━━━━━━━━ ✭ According to the Question : ➞ 1/R = 1/R₁ + 1/R₂ ... + 1/Rₙ ➞ 1/R = 1/2 + 1/2 + 1/2 + 1/2 ➞ 1/R = (1+1+1+1)/2 ➞ 1/R = 4/2 ➞ 1/R = 2/1 ➞ R = 1/2 ➞ R = 0.5 Ω So then Rₙₑₜ = 0.5 + 20 [Bcz they are connected in series] Rₙₑₜ = 20.5Ω

Answer»

Given

Four RESISTORS of 2Ω are CONNECTED parallely. They further are connected in SERIES with a 20Ω resistor

To Find

Equivalent resistance

Solution

☯ The equivalent resistance of a parallel COMBINATION is given by, 1/R = 1/R₁ + 1/R₂ ... + 1/Rₙ

━━━━━━━━━━━━━━━━━━━━━━━━━

✭ According to the Question :

➞ 1/R = 1/R₁ + 1/R₂ ... + 1/Rₙ

➞ 1/R = 1/2 + 1/2 + 1/2 + 1/2

➞ 1/R = (1+1+1+1)/2

➞ 1/R = 4/2

➞ 1/R = 2/1

➞ R = 1/2

➞ R = 0.5 Ω

So then Rₙₑₜ = 0.5 + 20 [Bcz they are connected in series]
Rₙₑₜ = 20.5Ω

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FIND EQUIVALENT RESISTANCE OF THE FOLLOWING COMBINATION.​

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FIND EQUIVALENT RESISTANCE OF THE FOLLOWING COMBINATION.