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Find k, if PQ || RS and P (2, 4), Q (3, 6), R (3,1), S (5, k). |
Answer» Slope of line PQ = (y2 -y1)/(x2 - x1) = (6 -4)/(3 - 2) = 2 Slope of line RS = (y2 -y1)/(x2 - x1) = (k - 1)/(5 - 3) = (k -1)/2 But, line PQ || line RS … [Given] ∴ Slope of line PQ = Slope of line RS ∴ 2 = (k -1)/2 ∴ 4 = k – 1 ∴ k = 4 + 1 ∴ k = 5 |
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