1.

Find k, if the sum of the zeroes of polynomial x²-(k+6)x+2(2k-1) is half their product?​

Answer»

Answer:

k=7

Explanation:

For given POLYNOMIAL x²-(k+6)x+2(2k-1)

Here

a=1 , B= -(k=6), c=2(2k-1)

GIVE that,

ஃ SUM of zeroes = ½ ( product of zeroes )

=> -[-(k+6)] = ½ ×2(2k-1)

______ _____

1 1

=> k+6 =2k-1

=> 6+1=2k-k

=> k=7

Therefore, the value of k=7


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