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Find number of photons in 6.62 J of radiant energy of frequency 102 Hz. (Takeh = 6.62 x 10-34 J-s)[2] |
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Answer» Given; E = 6.62J v = 10^14 Hz Let the no.of photons be x. =) E = x* hv =) 6.62 = x * 6.62 * 10^-34 Js * 10^14 =) 6.62/6.62 = x * 10^-20 =) 1 = x * 1/ 10^20 =) 10^20 = x. Hence correct answer is 10^20 photons. |
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