1.

Find number of photons in 6.62 J of radiant energy of frequency 102 Hz. (Takeh = 6.62 x 10-34 J-s)[2]

Answer»

Given;

E = 6.62J

v = 10^14 Hz

Let the no.of photons be x.

=) E = x* hv

=) 6.62 = x * 6.62 * 10^-34 Js * 10^14

=) 6.62/6.62 = x * 10^-20

=) 1 = x * 1/ 10^20

=) 10^20 = x.

Hence correct answer is 10^20 photons.



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