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Find out two-third `(2//3)` life of a first order reaction in which `k=5.48 xx 10^(-14)s^(-1)`A. `2.01xx10^(11)s`B. `2.01xx10^(13)s`C. `8.08xx10^(13)s`D. `16.04xx10^(11)s` |
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Answer» Correct Answer - B For two- third of a reaction, `[A]_(o)=a,[A]=a-(2a)/(3)rArra=(a)/(3)` `t_(2//3)=(2.303)/(k)"log"[A]_o/[A]=(2.303)/(k)"log"(a)/(a)=(2.303)/(k)log3` `t_(2//3)=(2.303xx0.4771)/(5.48xx10^(-14))=2.01xx10^(13)s` |
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