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Find position of centre of mass of four particle system, which are at the vertices of parallelogram, as shown in figure. |
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Answer» From figure `DC=bsin theta,OD=bcos theta` `x_(CM)=(m_(1)x_(1)+m_(2)x_(2)+m_(3)x_(3)+m_(4)x_(4))/(m_(1)+m_(2)+m_(3)+m_(4))` `x_(CM)=([a+bcos theta)]/2`, similarly `y_(CM)=(bsin theta)/2` `:. [x_(CM),y_(CM)]=[(a+bcostheta)/2,(bsintheta)/2]` |
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