1.

Find `tan^(-1)x/(sqrt(a^2-x^2))`in terms of `sin^(-1)`where `x in (0, a)dot`

Answer» `tan^(-1)(x/sqrt(a^2-x^2))=theta`
`tantheta=x/sqrt(a^2-x^2)`
`sintheta=x/a`
`theta=sin^(-1)(x/a)`.


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