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Find tension in each string and find acceleration |
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Answer» From above FIGURE (1) T=10a ...(1) 500−T=20a ...(2) From equation (1) and (2) a= 3 500 T= 3 500 N From above figure . (2) 500−T=10a (1) T=20a (2) From equation (1) and (2) 500=30a a= 3 500 m/s 2
and T= 3 1000 N |
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