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Find th equation of the hyperbola eccentricity is 2 and the distance between foci 16. |
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Answer» Here e 2 Distance between foci =2ae=16 `rArr" "2a(2)=16` `rArr" "a=4` and `b^(2)=a^(2)(e^(2)-1)` `=16(4-1)=48` `:.` Equation of hyperbola `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` `rArr" "(x^(2))/(16)-(y^(2))/(48)=1` `rArr" "3x^(2)-y^(2)=48`. |
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