1.

Find th equation of the hyperbola eccentricity is 2 and the distance between foci 16.

Answer» Here e 2
Distance between foci =2ae=16
`rArr" "2a(2)=16`
`rArr" "a=4`
and `b^(2)=a^(2)(e^(2)-1)`
`=16(4-1)=48`
`:.` Equation of hyperbola
`(x^(2))/(a^(2))-(y^(2))/(b^(2))=1`
`rArr" "(x^(2))/(16)-(y^(2))/(48)=1`
`rArr" "3x^(2)-y^(2)=48`.


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