Find the 10 th term of the HP `(3)/(2), 1, (3)/(4), (3)/(5), ...` – InterviewSolution

InterviewSolution

1.	Find the 10 th term of the HP `(3)/(2), 1, (3)/(4), (3)/(5), ...`
Answer» The given HP is `(3)/(2), 1, (3)/(4), (3)/(5),...` The corresponding AP is `(2)/(3), 1, (4)/(3), (5)/(3),...` Here `a = (2)/(3) , d = 1 - (2)/(3) = (1)/(3)` `therefore T_(10)` of the corresponding AP is `a+ (10-1) d = (2)/(3) = (9)(1)/(3) = (11)/(3)` Hence, required term in HP is `(3)/(11)`.

Discussion

No Comment Found

Related InterviewSolutions

Evaluate `sum2^(i)`, where `i=2, 3, 4, … , 10`.A. 2044B. 2048C. 1024D. 1022
Evaluate `sum(3+2^(r ))`, where `r=1, 2, 3, …, 10`.A. 2051B. 2049C. 2076D. 1052
Find the sum of the first 10 terms of geometric progression `18, 9, 4.5, …`A. `9((2^(10)-1))/(2^(8))`B. `9((2^(10)-1))/(2^(10))`C. `36((2^(10)-1)/(2^(8)))`D. `8((2^(10)-1))/(2^(8)) `
Find the sum of the series `1+ (1+2) + (1+2+3) + (1+2 + 3 +4)+ … + (1+2+3+… + 20)`.A. 1470B. 1540C. 1610D. 1370
If the 3rd, 7th and 11th terms of a geometric progression are `p, q and r` respectively, then the relation among `p, q and r` is ____.A. `p^(2) = qr`B. `r^(2) = qp`C. `q^(2) = p^(2r2)`D. `q^(2)= pr`
Geometic mean of `5, 10 and 20` is ______.
Find the sum fo the first 22 terms of an AP whose first term is 4 and the common difference is `(4)/(3)`.
Divide 124 into four parts in such a way that they are in AP and the product of the first and the 4 th part is 128 less than the product of the 2nd and the 3 rd parts.
If the sum of 16 terms of an AP is 1624 and the first term is 500 times the common difference, then find the common difference.A. 5B. `(1)/(2)`C. `(1)/(5)`D. `2`
Find the first term and the common difference of an AP, if the 3rd term is 6 and 17 th term is 34.